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Page 35 - CPVC Fire Sprinkler Products Installation Instructions & Technical Handbook
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``````  TECHNICAL DATA 33
Example: How much expansion can be expected in a 240 foot run of 2 inch TYCO CPVC Pipe installed in 40°F given a maximum temperature change to 100°F? Additionally, how long should the expansion loop be to compensate for this expansion?
Step 1. Find the temperature change expressed as ∆T. ∆T = 100°F – 40°F
∆T = 60°F
Step 2. Calculate the change in length expressed as ∆L. ∆L=12eL(∆T)
∆L = 12 (0.000034) x 240 x 60 ∆L = 5.88 inches
Step 3. Find the length of the expansion loop or offset in inches
L = Length of loop, offset, or charge of direction in inches
E = Modulus of elasticity at maximum temperature (Table L1)
in psi
D = Nominal outside diameter of pipe (Table D1) in inches S = Working stress at maximum temperature (Table L1) psi
∆L = Change in length of pipe due to a change in temperature from Step 2 in inches
L =71.90 inches
Step 4. Refer to Figure 7.
a-Forlooplength: 1/5L=1⁄5x71.90=14.38inches
2⁄5 L = 2⁄5 x 71.90 = 28.76 inches b- For offset length: 1⁄4 L = 1⁄4 x 71.90 = 17.98 inches
1⁄2 L = 1⁄2 x 71.90 = 35.95 inches c- For change of direction length: L= 71.90 inches
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